Asthma Essay Example | Topics and Well Written Essays - 500 words

Asthma - Essay Example It is important that therapists be familiar with asthma so that they can properly diagnose patients on an individual basis. As such, I picked these articles to review as each person is unique in their diagnosis, as well as their treatment. In Sherry Baker’s article, â€Å"Children in danger from exposure to common chemicals, new studies confirm,† the author divulges into alleged causes of asthma in children, which are the toxic chemicals of common products. One study revealed that children exposed to pesticides during their prenatal stage risked developing a chronic cough at the age of five. This study yields evidence that the respiratory system of a child is defenseless against toxic exposure while in their mother’s womb (Baker, 2012). This chemical found in pesticides that causes children to develop chronic cough is piperonyl butoxide. Two other chemicals that are known to cause chronic coughing in children include diethyl phthalate and butylbenzyl phthalate, which are found in personal care and plastic products. When children are exposed to these chemicals, they are at risk of developing asthma-related airway inflammation. Sarka-Jonae Miller looks at alternative remedies for asthma in her article â€Å"Lifestyle remedies for the management of asthma.† Miller points out that while doctors disagree with lifestyle remedies for asthma, such as acupuncture and breathing exercise, these treatments have been proven to be less harmful than the common prescribed medications (Miller, 2012). Rolfing and osteopathic manipulation can be utilized to alleviate restrictive patterns in muscles and nerves, allowing for easier breathing. Acupuncture has been shown to decrease the frequency of asthma attacks, as well as improve breathing. Various breathing exercises can be used to help individuals control their breathing, thus preventing asthma attacks and allowing individuals to rely less

Gender Roles and the Perception of Women Essay Example for Free

Gender Roles and the Perception of Women Essay There was a time that having a daughter born to a family evoked more pity than congratulations from the community. Sons were valued more for they were viewed to bring practical help towards augmenting the family income through physical labor, as well as ensuring that the family name lives on with his progeny. (Feminism) Daughters were valued only for the potential honor they could bring the family with a good marriage. In olden days, a good marriage was not necessarily defined by the couples happiness but rather was deemed as such if both families stand to benefit from the union. Usually benefits would be measured in wealth, alliance or business. Marriages then were basically mergers. Women were not expected to accomplish anything other than the mastery of domestic duties and union with a suitable husband. After marriage, the only duties that a woman is supposed to fulfill are to look after the needs of her husband and give birth to as many children as possible with preference to the birthing of sons. The 1920s and 30s saw a wave of feminism that sought to overturn the traditional gender role assigned to women. They viewed patriarchy as oppressive to women and advanced the thinking that women are complements of males and therefore should be treated as equals. The 1920s also saw a major victory for women in the United States with the passage of a law that allowed for womens suffrage. (Feminism) The Second World War in the 1940s also provided women with the opportunity to prove their worth outside their duties as homemakers. They started signing up as army nurses, members of womens corps and workers in factories that provided supplies and ammunition to the boys overseas. Even with this however, women still experienced discrimination at the hands of employers who believed that it was the mens role to earn money for their families. Those that were hired still had to face inequality in wages as their work were deemed easier compared to the mens. (Acker 46) It has continually been an uphill climb for women in the assertion of their rights and the fight for identity and equality. Despite the many progresses made by women since the olden days, some cultures still place more premium on males. Sandra Cisneros account (Kirszner, 96-99) of being and born and living in a traditional, patriarchal society in the 1950s show that even with the many new freedoms and rights accorded to women, their roles were still defined by marriage and domestic duties. What I didnt realize was that my father thought college was good for girls good for finding a husband. After four years of college and two more in graduate school, and still no husband, my father shakes his head even now and says I wasted all that education. (Kirszner 97) The selection further goes on to relate the attempts made by Cisneros in getting her father to acknowledge her achievements and herself as more than only a daughter. She wanted to BE his daughter in every sense of the word and enjoy the same pride her father has in her brothers achievements. I often witness the hunch posture, from women after dark on the warrenlike streets of Brooklyn where I live. They seem to set their faces on neutral and, with their purse straps strung across their chests bandolier style, they forge ahead as though bracing themselves against being tackled. (Kirszner 242) In Brent Staples observations in the Black Man effect in altering a public space (Kirszner 240), he presents the image of a woman who is determined to move forward yet remains aware of the possible challenges to her progress. While in the story the context women is defined in is couched in terms of potential threat from street violence and crimes, one could almost picture the same description as applicable to the grim and set determination of the feminists who steadfastly battles for womens rights and progress. It has been many years since women achieved a major victory in suffrage and set about to establishing their identity in society. Yet in some cases, there seem to be some women who remain oblivious or at least, not benefited by the new stature and rights women have been able to claim through years of struggle with a male-dominated society. In Anna Deavere Smiths Four American Characters monologue (2005) she shares a conversation she had with an elderly philosopher friend she had, Maxine Green. In the conversation, Smith asked Green: What are two things that you dont know and still want to know? Green replies: Personally I still feel that I have to curtsy when I see the president of our University and I feel that I ought to get coffee for my male colleagues even though Ive outlived most of them. Smith follows this up with the characterization of Maryland convict Paulette Jenkins. Paulette Jenkins represents the women in abusive relationship who suffer in silence. She never spoke out because she didnt want people to know that there was something wrong with her family. She took her husbands abuse and allowed him to do the same to her children†¦children that she had in the belief that it would soften her husband. What would make a man do such a thing? At the same time, what would make a woman stand by helplessly as her husband beats up her children and herself? Conflict in relationships between men and women are believed to stem from four main reasons: mens jealousy, mens expectation of women and domestic work, mens sense of right to punish their women, and the importance to men of asserting and keeping their authority. Women on the other hand, are kept silent due to feelings of shame and responsibility (Dobash, and Dobash 4). More often than not, the women feel that they deserved whatever the husband did to them. This acquiescence may be due to their cultural orientation of women as subservient wives. Upbringing and cultural orientation can do much to influence a persons understanding and acceptance of gender roles. (Dobash, and Dobash 4) However, there is always the freedom of choice and personal introspection, which should allow individuals to reason out right and wrong and the applicability and rationale of traditions for themselves. The case of Sandra Cisneros is the perfect illustration of this. Despite being brought up in a highly patriarchal household and culture, she chose to follow her own desire and achieve in her own right. In the end, she managed to earn her fathers respect and acknowledgment that she, as a woman, can accomplish and gain honor and pride for the family. Regardless of background, doctrine or culture, everyone, man and woman, has that same choice in choosing how their manhood or womanhood will be defined in their lives. Works Cited Acker, Joan. What Happened to the Womens Movement? -An Exchange. Monthly Review Oct. 2001: 46. Questia. 28 Sept. 2007 http://www. questia. com/PM. qst? a=od=5002421932. Feminism. The Columbia Encyclopedia. 6th ed. 2004. Questia. 28 Sept. 2007 http://www. questia. com/PM. qst? a=od=101243850. Dobash, R. Emerson, and Russell P. Dobash. Women, Violence, and Social Change. New York: Routledge, 1992. Questia. 28 Sept. 2007 http://www. questia. com/PM. qst? a=od=107605974. Kirszner, Laurie. Patterns for College Writing 10th ed. New York: Bedford/St. Martins. 2006. Mcneill, William H. Violence Submission in the Human Past. Daedalus 136. 1 (2007): 5+. Questia. 28 Sept. 2007 http://www. questia. com/PM. qst? a=od=5019968515. Smith, Anna Deveare. Four American Characters. 2005 TED. com. 27 Sept 2007 http://www. ted. com/index. php/talks/view/id/60

Writers of the Harlem Renaissance Essay -- Harlem Art Literature Essays

Writers of the Harlem Renaissance During the 1920?s, a ?flowering of creativity,? as many have called it, began to sweep the nation. The movement, now known as ?The Harlem Renaissance,? caught like wildfire. Harlem, a part of Manhattan in New York City, became a hugely successful showcase for African American talent. Starting with black literature, the Harlem Renaissance quickly grew to incredible proportions. W.E.B. Du Bois, Claude McKay, and Langston Hughes, along with many other writers, experienced incredible popularity, respect, and success. Art, music, and photography from blacks also flourished, resulting in many masterpieces in all mediums. New ideas began to take wings among circles of black intellectuals. The Renaissance elevated black works to a high point. Beyond simply encouraging creativity and thought in the African American community, the writers of the Harlem Renaissance completely revolutionized the identity of African American society as a whole, leading black culture from slavery to its current place in America today. There was no single cause which produced the Harlem Renaissance, but there are several historical developments which paved the way. The first set of contributing factors deal with the cultural background of Harlem from 1900 to 1920. At the turn of the century, Harlem first began to emerge as a distinctly black community. As black population increased, African American culture came to the surface and blacks started to hold prominent roles in this self-motivated community. This afro-centric atmosphere of Harlem appealed to many southern blacks, and as a result, ?the Great Migration of southern rural blacks to the north began in 1915? (Haskins 15). Blacks left segregation-... ...ier. New York: Harcourt, Brace, and World, Inc., 1970. 272. Locke, Alain. ?The New Negro.? Black Nationalism in America. John H. Bracey Jr. New York/Indianapolis: The Bobbs-Merrill Company Inc, 1970. 334-347. ?The Harlem Renaissance.? Rev. 9 Feb. 1998. 11 Feb. 2000 Wintz, Cary D. Black Culture and the Harlem Renaissance. Houston: Rice University Press, 1943. Works Consulted African American Literature Book Club. ?The Harlem Renaissance.? 14 Feb. 2000 Chambers, Veronica. The Harlem Renaissance. Philadelphia: Chelsea House Publishers, 1998. Franklin, John Hope. From Slavery to Freedom A History of Negro Americans. New York: Vintage Books, 1969. ?Harlem Renaissance.? 14 Feb. 2000 Lewis, David Levering. The Portable Harlem Renaissance Reader. New York: Viking Penguin, 1994. ?What is the Harlem Renaissance 14 Feb. 2000

Drugs and Medicine Options Report Essay

Medicine and drugs have been used throughout history in order to improve upon the well being of the world’s population. Both are used most commonly as a way to improve health by altering the physiological state, sensory sensations, and emotions which in some cases could all be the result of the placebo effect. Nonetheless, these drugs and medicines offer a unique advantage to our societies because of the ways that they can offer so much support to our bodies. An important thing to remember about these drugs and medicines is how unique each particular one is to a specific function of the body, meaning the chemistry behind it is also very unique for the many different functions. What makes medicines and drugs so unique in our particular society is their use as pain relievers, deficiency supplements, as well as their use to balance systems and organs in the body. However, in order for any of these uses to actually take effect it requires for that medicine or drug to somehow be ingested into the bloodstream so that it can travel to its necessary location in the body. One of the most common ways that this is done is through oral ingestion with tablets, syrups, or drops. These oral methods are much slower than the rest because of how much slower the rate of absorption into the bloodstream from the stomach is. A more common way as far as more extreme medicines go is something like an IV, where a needle is stuck directly into a vein so that the medicine is immediately worked into the bloodstream. However, the oral methods will most likely remain the most common because of how comfortably and easily they can be ingested by people. Prior to ever considering working a medicine or drug into the bloodstream, a long and extensive set of procedures must be carried out. This first begins with the isolation of the new product from other variables that could alter the testing. This new drug is then prescribed to laboratory testing where its effects can be observed and measured. If these established effects from the experimentation prove to be significant, a market is observed as a possible window for the drug to be sold in. Once the window has been considered, more of the final tests begin on actual humans where a placebo effect has been considered as well. After these final tests have been finished, the medicine must be approved by the Food and Drug Administration as either an over the counter drug or one that requires a prescription. Antacids are bases that neutralize the excess acidity and thus relieve the pain associated with heartburn and peptic ulcers (Brown). The most commonly used bases for the reduction of excess acidity in the stomach are those that are weak since strong bases would offer a support that would be much too corrosive to the body tissue. The most effective of these commonly used bases is aluminum hydroxide because of the fact that it can completely neutralize three moles of hydrochloric acid for every one mole of aluminum hydroxide that is used. Another common metal oxide that is used is magnesium oxide because of how quickly it reacts and thus offers relief, however since it reacts so quickly the relief does not last for as long as it does with the other bases. The metal carbonates used as bases offer an alternative to the metal oxides but they also react to create carbon dioxide which results in antifoaming agents being required as well to make sure that the users are not throwing up. As discussed above, there are specific types of drugs that can be known to help with pain relief; these drugs are known as analgesics. There are really two different type of analgesics, strong ones that are more commonly known as narcotics, and milder analgesics that are typically the over the counter pain relievers. The stronger analgesics work by binding with the actual pain receptors in the brain to block the transmission of the pain signals between brain cells (Jordan). These stronger analgesics are also able to trick the body’s brain cells by producing analgesia to produce a false sense of well being. The most common of the stronger analgesics are ones such as heroin, codeine, and morphine. In contrast to the stronger analgesics, the mild ones actually work by attacking the source of pain at that same location by helping to slow down with the production of prostaglandins, which are the actual chemicals that cause pain. The other way that these milder analgesics more commonly reduce pain is my reducing the inflammation by constricting the blood vessels near the pain source. The more frequently used of these milder analgesics are ones such as aspirin and ibuprofen that are typically in every household. Depressants are drugs prescribed by a doctor that affect the central nervous system by changing the concentration of neurotransmitters causing a decrease in brain activity and breathing rate (Jordan). There are three main types of depressants being barbiturates, benzodiazepines, and alcohol. Alcohol is probably the most well known of all three because of the large dependencies on it in our society today. While under the influence of alcohol, a person’s judgment and decision making becomes severely impaired which is what can so commonly lead to so many incidents involving alcohol. Aside from being temporarily impaired from alcohol, it can also lead to permanent brain damage as well as a high level of dependency on the alcohol which can completely alter one’s behavior. Stimulants are the type of medicine or drug that seems to have the complete opposite effect of the depressants. The most common of these stimulants are drugs such as amphetamine, adrenaline, nicotine, and caffeine. Adrenaline and amphetamine have many similarities as far as how they actually stimulate the body but they are different in the sense that adrenaline can be naturally produced by the body where as amphetamines are solely synthetically produced. Nicotine being another stimulant is best known for its role in the addiction of smokers to their cigarettes. Nicotine can be very harmful to the body however as it can lead to cancer and it is very difficult to stop using after it has first been used. Looking back on the drugs and medicine in our culture today it can easily be seen that they do have a very positive role in our society but because of the power that they possess they can also be dangerous when not used properly. It is sometimes heard on the news of people dying from drug overdoses that involve heroin or codeine but the only reason that these occurrences are even a problem at all is because of the personal abuse from those using those drugs. When used properly and only when suggested to by a doctor, the drugs and medicine that are in our culture today provide a huge advantage for us as we try to improve upon how well we live our lives today. The important thing to remember here is that it is nearly always necessary to regulate the changes in medicine and drugs in our society despite how well we may seem to have it under control.

Bluetooth Simulation

VIDYAVARDHINI’S COLLEGE OF ENGINEERING AND TECHNOLOGY ELECTRONICS AND TELECOMMUNICATION FINAL YEAR [2004-2005] A REPORT ON BLUETOOTH TECHNOLOGY PREPARED BY JANHAVI KHANOLKAR NAVEEN BITRA YASHESH MANKAD TABLE OF CONTENTS 1. INTRODUCTION 2. HISTORY 3. WHAT IS BLUETOOTH? 4. BLUETOOTH SPECIFICATIONS 5. BLUETOOTH NETWORKS 6. HOW DOES BLUETOOTH WORK? 7. BLUETOOTH PROTOCOL STACK 8. BLUETOOTH SECURITY 9. APPLICATIONS 10. MERITS AND DEMERITS INTRODUCTION: Bluetooth was originally conceived to replace the rat’s nest of cables typical in any PC setup today and this remains a compelling home application.However, as the Bluetooth evolved it became clear that it would also enable a totally new networking paradigm, Personal Area Networks (PANs)! With PAN technology a user will be able to organize a collection of personal electronic products (their PDA, cell phone, laptop, desktop, MP3 player, etc. ) to automatically work together. For instance the contact manager and calendar in the P DA, laptop, and desktop could all automatically synchronize whenever they are within range of each other). Over time PANs will revolutionize the user experience of consumer electronics.Finally, Bluetooth’s dynamic nature will also revolutionize connectivity to the rest of the world. Bluetooth will automatically discover devices and services nearby so available servers, internet access, printers etc. will automatically become visible to a Bluetooth device wherever it is. HISTORY: Bluetooth is an open specification for short range wireless voice and data communications that was originally developed for cable replacement in personal area networking to operate all over the world.By enabling standardized wireless communication between any electrical devices, Bluetooth has created the notion of a personal Area Network (PAN), a kind of close range wireless network that looks set to revolutionize the way people interact with the information technology landscape around them. In 1994 t he initial study for development of this technology started at Ericsson, Sweden. In 1998, Ericsson, Nokia, IBM, Toshiba, and Intel formed a Special Interest Group (SIG) to expand the concept and develop a standard under IEEE 802. 15 WPAN (Wireless Personal Area Network ).In 1999, the first specification was released and accepted as the IEEE 802. 15 WPAN standard for 1Mbps networks. The Bluetooth SIG considers three basic scenarios: †¢ The first basic scenario is the Cable Replacement ie. the wire replacement to connect a PC or laptop to its keyboard, mouse, microphone, and notepad. It avoids the multiple short range wiring surroundings of today’s personal computing devices. †¢ The second scenario is ad hoc networking of several different users at very short range in an area such as a conference room. The third scenario is to use Bluetooth as an AP to the wide area voice and data services provided by the cellular networks, wired connections or satellite links. Why th e name Bluetooth? The story of origin of name Bluetooth is interesting. †Bnluetooth† was the nickname of Harald Blaatand, 10th century Viking who united Denmark and Norway. When Bluetooth specification was introduced to public, a stone carving, erected from Harald Blaatand’s capital city Jelling was also presented. This strange carving was interpreted as Bluetooth connecting a cellular phone and a wireless notepad in his hands.The picture was used to symbolize the vision in using Bluetooth to connect personal computing and communication devices. What is BLUETOOTH? [pic] Figure1: Bluetooth system blocks The Bluetooth system consists of a radio unit, a link control unit, and a support unit for link management and host terminal interface functions (see Figure 1). The Host Controller Interface (HCI) provides the means for a host device to access Bluetooth hardware capabilities. For example, a laptop computer could be the host device and a PC card inserted in the PC is the Bluetooth device.All commands from the host to the Bluetooth module and events from the module to the host go through the HCI interface. The protocol stack is above the radio and baseband hardware, partly residing in the Bluetooth unit and partly in the host device. A Bluetooth solution can also be implemented as a one-processor architecture (embedded solution) where the application resides together with the Bluetooth protocols in the same hardware. In that case, the HCI is not needed. This is a feasible implementation for simple devices such as accessories or micro servers.Requirements of Bluetooth technology: †¢ If Bluetooth technology is to replace cables, it can not be much more expensive than a cable or nobody will buy it. †¢ Because Bluetooth technology is designed for mobile devices it must be able to run on batteries. So it must be very low power and should run on low voltages. †¢ It must also be lightweight and small enough not to intrude on the design o f compact mobile devices such as cellular phones, handsets etc. †¢ It must be as reliable as the cable it replaces and also it must be resilient. †¢ Bluetooth devices operate at 2. GHz in globally available, license free ISM band, which obey a basic set of power and spectral emission and interference specifications. THUS Bluetooth has to be very robust, as there are many existing users and polluters of this shared spectrum. Thus Bluetooth aims to be widely available, inexpensive, convenient, easy to use, reliable, small and low power. Specifications related with Bluetooth: |PARAMETER |VALUES | |Frequency Range |2. – 2. 4835 GHz | |Bandwidth of each channel |1MHz | |Data rate |1 Mbps | |Frequency hopping rate |1600 hops per seconds | |Range of operation |10-100 meters | Bluetooth system operates in 2. GHz Industrial Scientific Medicine (ISM) band. The operating band is divided into 1MHz spaced channels each signaling data at 1 Mbps so as to obtain maximum available channel bandwidth with chosen modulation scheme of GFSK (Gaussian Frequency Shift Keying). Using GFSK, a binary 1 give rise to a positive frequency deviation from the nominal carrier frequency while binary 0 gives rise to a negative frequency deviation. After each packet both devices retune their radio to a different frequency, effectively hopping from radio channel from radio channel.In this way Bluetooth devices use the whole of available ISM band and if transmission is compromised by interference on one channel, the retransmission will always be on a different channel. Each Bluetooth time slot lasts 625 microseconds giving rise to frequency hopping rate of 1600 hops per seconds. Generally devices hop once per packet. .For long data transmission, particular users may occupy multiple time slots using the same transmission frequency thus slowing instantaneous hopping rate to below 1600 hops/ sec. BLUETOOTH NETWORKS: PICCONETS AND SCATTERNET:The Bluetooth network is called a piconet . In the simplest case it means that two devices are connected (see Figure 2a). The device that initiates the connection is called a master and the other devices are called slaves. The majority of Bluetooth applications will be point-to-point applications. Bluetooth connections are typically ad hoc connections, which means that the network will be established just for the current task and then dismantled after the data transfer has been completed. A master can have simultaneous connections (point-to-multipoint) to up to seven slaves (see Figure2b).Then, however, the data rate is limited. One device can also be connected in two or more piconets. The set-up is called scatternet (see Figure 2c). A device can, however, only be a master to one piconet at a time. Support for hold, park, or sniff mode is needed for a device to be part of the scatternet. In these modes a device does not actively participate in a piconet, leaving time for other activities such as participating in another pic onet, for example. The master/slave roles are not necessarily fixed and can also be changed during the connection if, for example, the master does not have enough esources to manage the piconet. Master/slave switch is also needed in the scatternet. Master/slave switch support is not mandatory. Most of current Bluetooth implementations support piconets only. Point-to-multipoint support depends on the implementation Figure 2. Bluetooth piconet and scatternet scenarios: a) Point-to-point connection between two devices b) Point-to-multipoint connection between a master and three slaves c) Scatternet that consists of three piconets Modes of operation: In connection state, the Bluetooth unit can be in several modes of operation.Sniff, hold, and park modes are used to save power or to free the capacity of a piconet: Active mode: In the active mode, the Bluetooth unit actively participates on the channel. Sniff mode: In the sniff mode, the duty cycle of the slave’s listen activity ca n be reduced. This means that the master can only start transmission in specified time slots. Hold mode: While in connection state, the ACL link to a slave can be put in a hold (possible SCO links are still supported). In hold mode, the slave can do other things, such as scanning, paging, inquiring, or attending another piconet.Park mode: If a slave does not need to participate in the piconet but still wants to remain synchronized to the channel (to participate in the piconet again later), it can enter the park mode. It gives up its active member address. Park mode is useful if there are more than seven devices that occasionally need to participate in the same piconet. The parked slave wakes up regularly to listen to the channel in order to re-synchronize and to check for broadcast messages sent by the master.. FREQUENCY HOPPING :Bluetooth technology uses a frequency hopping technique, which means that every packet is transmitted on a different frequency. In most countries, 79 chann els can be used. With a fast hop rate (1600 hops per second), good interference protection is achieved. Another benefit is a short packet length. If some other device is jamming the transmission of a packet, the packet is resent in another frequency determined by the frequency scheme of the master. This scenario is depicted in Figure 3 where packets of device 1 (colored packets) and device 2 (banded packets) are trying to use the same frequency.Note that this case only refers to situations where there are two or more simultaneous active piconets or a non-Bluetooth device using the same frequency in range. The error correction algorithms are used to correct the fault caused by jammed transmissions Figure 4. Three-slot and five-slot long packets reduce overhead compared to one-slot packets. 220  µs switching time after the packet is needed for changing the frequency. Subsequent time slots are used for transmitting and receiving. The nominal slot length is 625 (s.A packet nominally c overs a single slot, but can be extended to cover three or five slots, as depicted in Figure 4. In multi-slot packets the frequency remains the same until the entire packet is sent. When using a multi-slot packet, the data rate is higher because the header and a 220 (s long switching time after the packet are needed only once in each packet. On the other hand, the robustness is reduced: in a crowded environment the long packets will more probably be lost HOW DOES BLUETOOTH WORKS? Bluetooth devices have 4 basic States.They can be a Master (in control of a Piconet — represented by a large blue circle above), an Active Slave (connected and actively monitoring/participating on a Piconet — medium orange circles), a Passive Slave (still logically part of a Piconet but in a low power, occasionally monitoring but still synchronized, inactive, state — medium gray circles), and Standby (not connected to a Piconet, occasionally monitoring for inquiries from other devices, but not synchronized with any other devices — small white circles). IN IDEAL STATE Bluetooth devices initially know only about themselves and in this state they will be in Standby mode.Standby is a passive mode where a Bluetooth device listens on an occasional basis performing what are called Inquiry and/or Page Scans for 10 milliseconds out of every 1. 28 seconds to see if any other Bluetooth devices are looking to communicate. Passive behavior is inherent to half of Bluetooth’s states and is a key mechanism to achieving very low power. In Standby mode the Bluetooth device’s occasional attention reduces power consumption by over 98%. While all of the Bluetooth devices in the same mode it is important to note that they are NOT synchronized or coordinated in any way.Thus they are all listening at different times and on different frequencies. [pic] Enquiry and page procedures lead to connections ENQUIRY: Inquiry is how a Bluetooth device learns about other devices that are within its range. In the illustration above Node A executes a Page Function on the BT Inquiry ID and receives replies from other devices. Through these replies device A learns the explicit identity of these other devices (i. e. their unique Bluetooth device ID). During the Inquiry process device A continuously broadcasts the Page command using the reserved Inquiry ID which identifies it as as a Page Inquiry.These broadcasts are spread across a standard pattern of 32 Standby radio frequencies which all devices in Standby mode monitor on an occasional basis. Over a duration of some seconds it is certain that every Standby device within range will have received the Inquiry Page even though they are not synchronized in any way. By convention these nodes will respond with a standard FHS packet that provides their unique BT ID and their clock offset. With these parameters the Inquiring node can effect low latency synchronized connections.Node H (the dotted circle above) illustra tes how a Bluetooth device can be programmed to remain anonymous (Undiscoverable in BT jargon). This is a user controlled feature that suspends Inquiry Scanning, and thus device A’s Inquiry Procedure cannot discover Device B It is important to note that device H will continue to support Page Scanning however, and thus a user’s other personal devices (i. e. PAN) can penetrate this barrier by Paging directly to its unique Bluetooth ID. This is information that PAN devices can be configured to know and remember thus enabling private collaboration even when devices are undiscoverable.PAGING: In its general form the Page command establishes a formal device to device link between a Master (the originator) and a Slave. Master/Slave connections in Bluetooth are referred to as a Piconet. To create the piconet device A broadcasts the Page command with the explicit device ID of the target Slave (B in the illustration above) which was learned earlier through an Inquiry Procedure. Further, this connection can be very low latency if the Inquiry data is recent (and thus synchronization can be accurate), but the process will simply take longer if this is not the case.All Bluetooth devices except B will ignore this command as it is not addressed to them. When the device B replies, device A will send it an FHS packet back and assign it an Active Member Address in the Piconet. As an Active Slave device B will begin continuously monitoring for further commands from device A in synchronization with device A’s hopping pattern and clock offset. Further, standard Piconet activity continuously updates the clock offset data keeping the synchronization extremely accurate. Thus the Master and Slave states are not low power but exhibit very low transaction latencies. EXPANDING A PICCONET:Through successive Page commands a Bluetooth Master can attach up to 7 Active Slaves. 7 is a hard limit as only 3 bits are allocated in Bluetooth for the Active Member Address (AMA) w ith 000 reserved for the Master and the remaining addresses allocated to Slaves. Practically, 7 is more than sufficient given Bluetooth’s modest performance and dynamic configurability. Again, all Active Slaves to A continuously monitor for further commands addressed to them in synchronization with device A’s hopping pattern. PARKING: Parking is a mechanism that allows a Bluetooth Master to connect to an additional 256 devices. 56 is a hard limit as 8 bits are allocated in Bluetooth for the Parked Member Address (PMA). To Park a device the Bluetooth Master issues a Park command to an Active Slave and assigns it a PMA. This Slave then enters the Parked mode and surrenders its AMA. As a Parked Slave the device will revert to a passive mode and only monitor for commands on an occasional basis. The difference between Standby and Parked however is that the Slave will remain synchronized to the Master’s hopping pattern and regularly update its clock offset. Thus this device can be reconnected at any time with a minimum latency.BLUETOOTH PROTOCOLS: Protocols are needed to implement different profiles and usage models. Every profile uses at least part of the protocol stack. In order to achieve interoperability between two Bluetooth devices, they both must have the same vertical profile of the protocol stack. Bluetooth Core Protocols Baseband and Link Control together enable a physical RF link between Bluetooth units forming a piconet. This layer is responsible for synchronizing the transmission-hopping frequency and clocks ofdifferent Bluetooth devices [Whitepaper1, p. ]. Audio is routed directly to and from Baseband. Any two Bluetooth devices supporting audio can send and receive audio data between each other just by opening an audio link . Link Manager Protocol (LMP) is responsible for link set-up (authentication and encryption, control, and negotiation of baseband packets) between Bluetooth devices and for power modes and connection states of a Bluetooth unit. Logical Link Control and Adaptation Protocol (L2CAP) takes care of multiplexing, reassembly, and segmentation of packets.Service Discovery Protocol (SDP) is needed when requesting device information, services, and the characteristics of other devices. Devices have to support the same service in order to establish a connection with each other. Cable Replacement Protocol RFCOMM emulates RS-232 signals and can thus be used in applications that were formerly implemented with a serial cable (e. g. , a connection between a laptop computer and a mobile phone). Telephony Protocol Binary (TCS-BIN) defines the call control signaling for the establishment of speech and data call between Bluetooth devices.AT commands provide means for controlling a mobile phone or a modem. Adopted Protocols OBEX (Object Exchange) is adopted from IrDA. It is a session protocol that provides means for simple and spontaneous object and data transfer. It is independent of the transport mechanism an d transport Application Programming Interface (API). TCP/UDP/IP is defined to operate in Bluetooth units allowing them to communicate with other units connected, for instance, to the Internet. The TCP/IP/PPP protocol configuration is used for all Internet Bridge usage scenarios in Bluetooth 1. and for OBEX in future versions. The UDP/IP/PPP configuration is available as transport for WAP. PPP in the Bluetooth technology is designed to run over RFCOMM to accomplish point-to-point connections. PPP is a packet-oriented protocol and must therefore use its serial mechanisms to convert the packet data stream into a serial data stream. The Wireless Application Protocol (WAP) stack can reside on top of RFCOMM (based on LAN Access Profile) or on top of L2CAP (based on PAN Profile). The latter reduces overhead and is likely to become the preferred solution for WAP over Bluetooth.Wireless Application Environment (WAE) hosts the WAP browser environment. Dial up networking (DUN) profile protocol stack: DUN profile is inside the Serial Port Profile and therefore partly reuses the capabilities of the Serial Port Profile. For the DUN Profile, there are two device configurations (roles): †¢ Gateway (GW) is the device that provides access to the public network (typically mobile phones and modems) †¢ Data terminal (DT) is the device that uses the dial-up services of the gateway (typically PCs) The DUN Profile needs a two-piece protocol stack and an SDP branch.PPP over RFCOMM is needed for transferring payload data. AT commands are delivered over RFCOMM to control the modem (mobile phone). The application on top of the stack is either a driver application on a PC (data terminal) or the modem emulation on a phone (gateway). Bluetooth security: secret key All Bluetooth devices (master and slave) share a secret key in a particular system. This key is used during the authentication and encryption process. This key is not transmitted over the channel but is rather in-built b y the manufacturer. AUTHENTICATIONAuthentication ensures the identity of Bluetooth devices. Authorization is a process of deciding if a device is allowed to have access to a specific service. User interaction may be required unless the remote device has been marked as â€Å"trusted. † Usually the user an set authorization on/off to every remote device separately. Authorization always requires authentication. Authentication in Bluetooth is performed by an encryption engine which uses the SAFER+ algo. This algorithm requires the following: †¢ Number to be encrypted or decrypted †¢ master address †¢ Master clock secret key shared by master and slave. A random number is generated by the encryption engine using various keys. This random number is encrypted by the master using the secret key. This number is also sent to the slave. The encrypted reply of the slave is compared with the master encrypted data. If it is a match then the slave is authentic. BONDING AND PAI RING Pairing is a procedure that authenticates two devices based on a common passkey, thereby creating a trusted relationship between those devices. An arbitrary but identical passkey must be entered on both devices.As long as both devices are paired, the pairing procedure is not required when connecting those devices again (the existing link key is used for authentication). Devices without any input method, like headsets, have fixed passkeys. When two devices are linked with a common link the connection is called as bonding. There are two types of bonding: †¢ Dedicated bonding: Used to create and exchange a link key between two devices. †¢ General bonding: Data over the link is available for higher layers. ENCRYPTION Encryption protects communication against eavesdropping.For example, it ensures that nobody can listen to what a laptop transmits to a phone. Encryption demands the following: †¢ Negotiating encryption mode †¢ Negotiating key sizes-The key size coul d vary from 8 to 128 bits †¢ Starting encryption †¢ Stopping encryption SECURITY LEVELS A trusted device has been previously authenticated, a link key is stored, and the device is marked as â€Å"trusted† in the security database of a device. The device can access Bluetooth services without user acceptance. An untrusted device has been previously authenticated, a link key is stored, but the device is not marked as â€Å"trusted. Access to services requires acceptance of the user. An unknown device means that there is no security information on this device. This is also an untrusted device. Security Level of Services Authorization required: Access is only granted automatically to trusted devices or untrusted devices after an authorization procedure (‘Do you accept connection from remote device? ’). Authentication is always required. Authentication required: The remote device must be authenticated before connecting to the application. Encryption required : The link must be changed to encrypted before accessing the service.It is also possible that a service does not require any of these mechanisms. On the other hand, the application (service) might have its own user authentication mechanisms (a PIN code, for example). APPLICATIONS: 1. Bluetooth in the home will ultimately eliminate most every cable related to consumer electronics (except power). Your PC, scanner, and printer will simply need to be within 10 meters of each other in order to work. Your PDA, digital camera, and MP3 player will no longer need a docking station to transfer files or get the latest tunes (the exception will be to recharge, that power thing again).And, your home stereo and other equipment will join the party too. On the telephone front your cell phone will synchronize its address book with your PC and function as a handset to your cordless phone in the house (answering incoming calls to your home number and calling out on the cheaper land line too). Finally, even though its only 720Kbps, Bluetooth is still pretty fine for broadband internet access since DSL and cable modems are typically throttled to about 384K anyway. Bluetooth access points could well be as ubiquitous as 56K modems in 2 or 3 years. . On the road much of your Bluetooth PAN goes with you. Even when your laptop is in your briefcase and your cell phone is in your pocket they will be able to collaborate to access e-mail. And, next generation cell phones featuring Bluetooth and General Packet Radio (GPR) technology will function as a wireless modems with internet access at 100Kbps+. With such performance it is likely web based e-business will flourish and these devices will become the most prevalent Bluetooth access points.This may well be the Killer App that ensures Bluetooth’s widespread adoption and success. When you are literally on the road your car will join your PAN too. Here your cell phone may operate in a hands free mode using the car audio system and an i n-dash microphone even while comfortably in your pocket. Or you may use a wireless Bluetooth headset instead. And, your MP3 player will likely play music in 8 speaker surround sound, rip music right off of an FM broadcast, or record your phone calls for later review. And all without wires!!!Fixed land line access points (supporting up to 720Kbps) such as a pay phone in the airport terminal or lounge, or the desk phone in your hotel, will provide true broadband access in these strategic locations. Also look for the pay phone to evolve to compete for your cell phone calls too with its low cost land lines. In the world of deregulation and open competition future smart phones may even put your calls out for bid and channel the traffic over the carrier offering the lowest cost! 3. Telephone applications †¢ Hands free use †¢ File synchronization †¢ Calendars †¢ Contact management Land line I/F for voice and data 4. Consumer applications †¢ File transfer †¢ MP 3 †¢ Digital pictures †¢ Peripheral connectivity †¢ Keyboard/mouse/remote †¢ Printer ADVANTAGES: 1. Point to point and point to multiple links 2. Voice and data links 3. Compact form factor 4. Low power 5. Low cost 6. Robust frequency hopping and error correction 7. Profiles ensure application level 8. High level of security through frequency hopping, encryption and authentication 9. Non directional 10. Unlicensed ISM band LIMITATIONS: 1. 8 Devices per piconet with limited extension via scatternet 2.Short range 3. No handover facility 4. Maximum data rate of 723. 2 Kb/s 5. occupies the crowded ISM band 6. Slow connection setup References: †¢ Bluetooth 1. 1 —Jenifer Bray †¢ Wireless Communication -Krishnamurthy †¢ Bluetooth Specifications, Bluetooth SIG at http://www. bluetooth. com †¢ Bluetooth Protocol Architecture v1. 0, Riku Mettala, Bluetooth SIG, August 1999 http://www. bluetooth. org/foundry/sitecontent/document/whitepapers_presen tations †¢ Bluetooth Security Architecture, Thomas Muller, Bluetooth SIG, July 1999 http://www. bluetooth. rg/foundry/sitecontent/document/whitepapers_presentations †¢ Comprehensive Description of the Bluetooth System v0. 9p, Dan Sonnerstam, Bluetooth SIG, May 1998 http://info. nsu. ac. kr/cwb-data/data/ycra2/comprehensive_description_of_the_BT_system. pdf †¢ Bluetooth Technology Overview, version 1. 0, April 2003 http://forum. nokia. com ———————– [pic] Digital Camera Computer Scanner Home Audio System MP3 Player PDA Cell Phone Operational States Master Active Slave Parked Slave* Standby* ON THE ROAD Laptop PDA Cell Phone MP3 Player Headset Hotel Phone & Access Point

Overcome Laziness and Become a Successful Person

Overcome Laziness and Become a Successful Person Get Things Done: Overcoming Laziness Even though all of us are mortal, for some reason we dont seem to care that we have limited time on this planet. To find purpose, to love, to see the world, to know thyself to accomplish all these things, we have on average 70 years if were lucky. If not, we have even less time. Unfortunately, laziness and procrastination is in our nature. However, in every human theres also a successful person, who cant reveal him/herself without the right effort. The question is how can we wake this successful person up and deal with laziness and procrastination? How can we start valuing the precious moments that we have on this wonderful planet and begin doing something that really matters? Lets look at these five tips to help you beat laziness quickly: Take action. As simple as that. If you dont want to write, sit down and start writing. If you dont want to read, sit down and start reading. If you dont feel like exercising youve got the idea. Procrastination happens when you listen to that Gollum voice in your head. With all your strength, make it shut up and just start doing what you need to do. You can never start if you keep listening to it. One bite at a time. Imagine that you are served with a delicious meal and told that you need to eat it in one bite; otherwise, it will be taken away. Could you do this? None of us could, because fortunately we have normal-sized mouths. So, if you cant do that, why to project this one giant bite attitude to your daily tasks? Take one bite at a time and you can even start finding your tasks pleasurable. On the other hand, if you try to do everything at once, you will do nothing and lose the motivation. Most of the time, it is we who make our lives difficult. Remove the distractions. When we dont want to do something, even such things as cleaning the closet, start to look for an attractive side. We also tend to follow different distractions around us watch TV series, scroll Facebook pages, read blogs etc. Focus on what youre doing without any distractions (disconnect the Internet, turn off the TV and put your phone on a fly-mode) and take some rest when youre done. Find motivation. Remind yourself how important is what youre doing. If the things youre doing stopped being important, then its time for introspection and recapping your goals. Reward yourself. Of course, you dont want to become a robot. And you dont have to; you can reward yourself after each completed task. In fact, this is one of the greatest ways to stay motivated. Take a little nap, go for a 15-minute walk, or perform some activity that you like. This way, you will have more motivation to get things done. The most difficult part in overcoming laziness is taking action. So, heres a final straightforward recommendation turn off that bad friends voice in your head, and just start making things happen.

Complete Guide to Integers on SAT Math (Advanced)

Complete Guide to Integers on SAT Math (Advanced) SAT / ACT Prep Online Guides and Tips Integer questions are some of the most common on the SAT, so understanding what integers are and how they operate will be crucial for solving many SAT math questions. Knowing your integers can make the difference between a score you’re proud of and one that needs improvement. In our basic guide to integers on the SAT (which you should review before you continue with this one), we covered what integers are and how they are manipulated to get even or odd, positive or negative results. In this guide, we will cover the more advanced integer concepts you’ll need to know for the SAT. This will be your complete guide to advanced SAT integers, including consecutive numbers, primes, absolute values, remainders, exponents, and roots- what they mean, as well as how to handle the more difficult integer questions the SAT can throw at you. Typical Integer Questions on the SAT Because integer questions cover so many different kinds of topics, there is no â€Å"typical† integer question. We have, however, provided you with several real SAT math examples to show you some of the many different kinds of integer questions the SAT may throw at you. Over all, you will be able to tell that a question requires knowledge and understanding of integers when: #1: The question specifically mentions integers (or consecutive integers). Now this may be a word problem or even a geometry problem, but you will know that your answer must be in whole numbers (integers) when the question asks for one or more integers. If $j$, $k$, and $n$ are consecutive integers such that $0jkn$ and the units (ones) digit of the product $jn$ is 9, what is the units digit of $k$? A. 0B. 1C. 2D. 3E. 4 (We will go through the process of solving this question later in the guide) #2: The question deals with prime numbers. A prime number is a specific kind of integer, which we will discuss in a minute. For now, know that any mention of prime numbers means it is an integer question. What is the product of the smallest prime number that is greater than 50 and the greatest prime number that is less than 50? (We will go through the process of solving this question later in the guide) #3: The question involves an absolute value equation (with integers) Anything that is an absolute value will be bracketed with absolute value signs which look like this:| | For example: $|-210|$ or $|x + 2|$ $|10 - k| = 3$ $|k - 5| = 8$ What is a value for k that fulfills both equations above? (We will go through how to solve this problem in the section on absolute values below) Note: there are several different kinds of absolute value problems. About half of the absolute value questions you come across will involve the use of inequalities (represented by $$ or $$). If you are unfamiliar with inequalities, check out our guide to inequalities. The other types of absolute value problems on the SAT will either involve a number line or a written equation. The absolute value questions involving number lines almost always use fraction or decimal values. For information on fractions and decimals, look to our guide to SAT fractions. We will be covering only written absolute value equations (with integers) in this guide. #4: The question uses perfect squares or asks you to reduce a root value A root question will always involve the root sign: $√$ $√81$, $^3√8$ You may be asked to reduce a root, or to find the square root of a perfect square (a number that is the square of an integer). You may also need to multiply two or more roots together. We will go through these definitions as well as how all of these processes are done in the section on roots. (Note: A root question with perfect squares may involve fractions. For more information on this concept, look to our guide on fractions and ratios.) #5: The question involves multiplying or dividing bases and exponents Exponents will always be a number that is positioned higher than the main (base) number: $2^7$, $(x^2)^4$ You may be asked to find the values of exponents or find the new expression once you have multiplied or divided terms with exponents. We will go through all of these questions and topics throughout this guide in the order of greatest prevalence on the SAT. We promise that integers are a whole lot less mysterious than...whatever these things are. Exponents Exponent questions will appear on every single SAT, and you will likely see an exponent question at least twice per test. An exponent indicates how many times a number (called a â€Å"base†) must be multiplied by itself. So $4^2$ is the same thing as saying $4 * 4$. And $4^5$ is the same thing as saying $4 * 4 * 4 * 4 * 4$. Here, 4 is the base and 2 and 5 are the exponents. A number (base) to a negative exponent is the same thing as saying 1 divided by the base to the positive exponent. For example, $2^{-3}$ becomes $1/2^3$ = $1/8$ If $x^{-1}h=1$, what does $h$ equal in terms of $x$? A. $-x$B. $1/x$C. $1/{x^2}$D. $x$E. $x^2$ Because $x^{-1}$ is a base taken to a negative exponent, we know we must re-write this as 1 divided by the base to the positive exponent. $x^{-1}$ = $1/{x^1}$ Now we have: $1/{x^1} * h$ Which is the same thing as saying: ${1h}/x^1$ = $h/x$ And we know that this equation is set equal to 1. So: $h/x = 1$ If you are familiar with fractions, then you will know that any number over itself equals 1. Therefore, $h$ and $x$ must be equal. So our final answer is D, $h = x$ But negative exponents are just the first step to understanding the many different types of SAT exponents. You will also need to know several other ways in which exponents behave with one another. Below are the main exponent rules that will be helpful for you to know for the SAT. Exponent Formulas: Multiplying Numbers with Exponents: $x^a * x^b = x^[a + b]$ (Note: the bases must be the same for this rule to apply) Why is this true? Think about it using real numbers. If you have $2^4 * 2^6$, you have: $(2 * 2 * 2 * 2) * (2 * 2 * 2 * 2 * 2 * 2)$ If you count them, this give you 2 multiplied by itself 10 times, or $2^10$. So $2^4 * 2^6$ = $2^[4 + 6]$ = $2^10$. If $7^n*7^3=7^12$, what is the value of $n$? A. 2B. 4C. 9D. 15E. 36 We know that multiplying numbers with the same base and exponents means that we must add those exponents. So our equation would look like: $7^n * 7^3 = 7^12$ $n + 3 = 12$ $n = 9$ So our final answer is C, 9. $x^a * y^a = (xy)^a$ (Note: the exponents must be the same for this rule to apply) Why is this true? Think about it using real numbers. If you have $2^4 * 3^4$, you have: $(2 * 2 * 2 * 2) * (3 * 3 * 3 * 3)$ = $(2 * 3) * (2 * 3) * (2 * 3) * (2 * 3)$ So you have $(2 * 3)^4$, or $6^4$ Dividing Exponents: ${x^a}/{x^b} = x^[a-b]$ (Note: the bases must be the same for this rule to apply) Why is this true? Think about it using real numbers. ${2^6}/{2^2}$ can also be written as: ${(2 * 2 * 2 * 2 * 2 * 2)}/{(2 * 2)}$ If you cancel out your bottom 2s, you’re left with $(2 * 2 * 2 * 2)$, or $2^4$ So ${2^6}/{2^2}$ = $2^[6-2]$ = $2^4$ If $x$ and $y$ are positive integers, which of the following is equivalent to $(2x)^{3y}-(2x)^y$? A. $(2x)^{2y}$B. $2^y(x^3-x^y)$C. $(2x)^y[(2x)^{2y}-1]$D. $(2x)^y(4x^y-1)$E. $(2x)^y[(2x)^3-1]$ In this problem, you must distribute out a common element- the $(2x)^y$- by dividing it from both pieces of the expression. This means that you must divide both $(2x)^{3y}$ and $(2x)^y$ by $(2x)^y$. Let's start with the first: ${(2x)^{3y}}/{(2x)^y}$ Because this is a division problem that involves exponents with the same base, we say: ${(2x)^{3y}}/{(2x)^y} = (2x)^[3y - y]$ So we are left with: $(2x)^{2y}$ Now, for the second part of our equation, we have: ${(2x)^y}/{(2x)^y}$ Again, we are dividing exponents that have the same base. So by the same process, we would say: ${(2x)^y}/{(2x)^y} = (2x)^[y - y] = (2x)^0 = 1$ (Why 1? Because, as you'll see below, anything raised to the power of 0 = 1) So our final answer looks like: ${(2x)^y}{((2x)^{2y} - 1)}$ Which means our final answer is C. Taking Exponents to Exponents: $(x^a)^b = x^[a * b]$ Why is this true? Think about it using real numbers. $(2^3)^4$ can also be written as: $(2 * 2 * 2) * (2 * 2 * 2) * (2 * 2 * 2) * (2 * 2 * 2)$ If you count them, 2 is being multiplied by itself 12 times. So $(2^3)^4 = 2^[3 * 4] = 2^12$ $(x^y)^6 = x^12$, what is the value of $y$? A. 2B. 4C. 6D. 10E. 12 Because exponents taken to exponents are multiplied together, our problem would look like: $y * 6 = 12$ $y = 2$ So our final answer is A, 2. Distributing Exponents: $(x/y)^a = {x^a}/{y^a}$ Why is this true? Think about it using real numbers. $(2/4)^3$ can be written as: $(2/4) * (2/4) * (2/4)$ $8/64 = 1/8$ You could also say $2^3/4^3$ = $8/64$ = $1/8$ $(xy)^z = x^z * y^z$ If you are taking a modified base to the power of an exponent, you must distribute that exponent across both the modifier and the base. $(3x)^3$ = $3^3 * x^3$ (Note on distributing exponents: you may only distribute exponents with multiplication or division- exponents do not distribute over addition or subtraction. $(x + y)^a$ is NOT $x^a + y^a$, for example) Special Exponents: For the SAT you should know what happens when you have an exponent of 0: $x^0=1$ where $x$ is any number except 0 (Why any number but 0? Well 0 to any power other than 0 is 0, because $0x = 0$. And any other number to the power of 0 is 1. This makes $0^0$ undefined, as it could be both 0 and 1 according to these guidelines.) Solving an Exponent Question: Always remember that you can test out exponent rules with real numbers in the same way that we did above. If you are presented with $(x^2)^3$ and don’t know whether you are supposed to add or multiply your exponents, replace your x with a real number! $(2^2)^3 = (4)^3 = 64$ Now check if you are supposed to add or multiply your exponents. $2^[2+3] = 2^5 = 32$ $2^[2 * 3] = 2^6 = 64$ So you know you’re supposed to multiply when exponents are taken to another exponent. This also works if you are given something enormous, like $(x^23)^4$. You don’t have to test it out with $2^23$! Just use smaller numbers like we did above to figure out the rules of exponents. Then, apply your newfound knowledge to the larger problem. And the philosophical debate continues. Roots Root questions are common on the SAT, and you should expect to see at least one during your test. Roots are technically fractional exponents. You are likely most familiar with square roots, however, so you may have never heard a root expressed in terms of exponents before. A square root asks the question: "What number needs to be multiplied by itself one time in order to equal the number under the root sign?" So $√36 = 6$ because 6 must be multiplied by itself one time to equal 36. In other words, $6^2 = 36$ Another way to write $√36$ is to say $^2√36$. The 2 at the top of the root sign indicates how many numbers (2 numbers, both the same) are being multiplied together to become 36. (Note: you do not expressly need the 2 at the top of the root sign- a root without an indicator is automatically a square root.) So $^3√27 = 3$ because three numbers, all of which are the same ($3 * 3 * 3$), multiplied together equals 27. Or $3^3 = 27$. Fractional Exponents If you have a number to a fractional exponent, it is just another way of asking you for a root. So $16^{1/2} = ^2√16$ To turn a fractional exponent into a root, the denominator becomes the value to which you take the root. But what if you have a number other than 1 in the numerator? $16^{2/3} = ^3√16^2$ The denominator becomes the value to which you take the root, and the numerator becomes the exponent to which you take the number under the root sign. Distributing Roots $√xy = √x * √y$ Just like with exponents, roots can be separated out. So $√20$ = $√2 * √10$ or $√4 * √5$ $√x * √y = √xy$ Because they can be separated, roots can also come together. So $√2 * √10$ = $√20$ Reducing Roots It is common to encounter a problem with a mixed root, where you have an integer multiplied by a root (like $3√2$). Here, $3√2$ is reduced to its simplest form, but let's say you had something like this instead: $2√12$ Now $2√12$ is NOT as reduced as it can be. In order to reduce it, we must find out if there are any perfect squares that factor into 12. If there are, then we can take them out from under the root sign. (Note: if there is more than one perfect square that can factor into your number under the root sign, use the largest one.) 12 has several factor pairs. These are: $1 * 12$ $2 * 6$ $3 * 4$ Well 4 is a perfect square because $2 * 2 = 4$. That means that $√4 = 2$. This means that we can take 4 out from under the root sign. Why? Because we know that $√xy = √x * √y$. So $√12 = √4 * √3$. And $√4 = 2$. So 4 can come out from under the root sign and be replaced by 2 instead. $√3$ is as reduced as we can make it, since it is a prime number. We are left with $2√3$ as the most reduced form of $√12$ (Note: you can test to see if this is true on most calculators. $√12 = 3.4641$ and $2 *√3 = 2 * 1.732 = 3.4641$. The two expressions are identical.) Now to finish the problem, we must multiply our reduced form of $√12$ by 2. Why? Because our original expression was $2√12$. $2 * 2√3 = 4√3$ So $2√12$ in its most reduced form is $4√3$ Remainders Questions involving remainders generally show up at least once or twice on any given SAT. A remainder is the amount left over when two numbers do not divide evenly. If you divide 12 by 4, you will not have any remainder (your remainder will be zero). But if you divide 13 by 4, you will have a remainder of 1, because there is 1 left over. You can think of the division as $13/4 = 3{1/4}$. That extra 1 is left over. Most of you probably haven’t worked with integer remainders since elementary school, as most higher level math classes and questions use decimals to express the remaining amount after a division (for the above example, $13/4 = 3 \remainder 1$ or $3.25$). But for some situations, decimals simply do not apply. Joanne’s hens laid a total of 33 eggs. She puts them into cartons that fit 6 eggs each. How many eggs will she have left that do NOT make a full carton of eggs? $33/6 = 5 \remainder 3$. So Joanne can make 5 full baskets with 3 eggs left over. Some remainder questions may seem incredibly obscure, but they are all quite basic once you understand what is being asked of you. Which of the following answers could be the remainders, in order, when five positive consecutive integers are divided by 4? A. 0, 1, 2, 3, 4B. 2, 3, 0, 1, 2C. 0, 1, 2, 0, 1D. 2, 3, 0, 3, 2E. 2, 3, 4, 3, 2 This question may seem complicated at first, so let’s break it down into pieces. The question is asking us to find the list of remainders when positive consecutive integers are divided by 4. This means we are NOT looking for the answer plus remainders- we are just trying to find the remainders by themselves. We will discuss consecutive integers below in the guide, but for now understand that "positive consecutive integers" means positive integers in a row along a number line. So positive consecutive integers increase by 1 continuously. , 12, 13, 14, 15, etc. are an example of positive consecutive integers. We also know that any number divided by 4 can have a maximum remainder of 3. Why? Because if any number could be divided by 4 with a remainder of 4 left over, it means it could be divided by 4 one more time! For example, $16/4 = 4 \remainder 0$ because 4 goes into 16 exactly 4 times. (It is NOT $3 \remainder 4$.) So that automatically lets us get rid of answer choices A and E, as those options both include a 4 for a remainder. Now we also know that, when positive consecutive integers are divided by any number, the remainders increase by 1 until they hit their highest remainder possible. When that happens, the next integer remainder resets to 0. This is because our smaller number has gone into the larger number an even number of times (which means there is no remainder). For example, $10/4 = 2 \remainder 2$, $/4 = 2 \remainder 3$, $12/4 = 3 \remainder 0$, and $13/4 = 3 \remainder 1$ Once the highest remainder value is achieved (n - 1, which in this case is 3), the next remainder resets to 0 and then the pattern repeats again from 1. So we’re looking for a pattern where the remainders go up by 1, reset to 0 after the remainder = 3, and then repeat again from 1. This means the answer is B, 2, 3, 0, 1, 2 Luckily, Joanne's remaining eggs did not go unloved for long. Prime numbers The SAT loves to test students on prime numbers, so you should expect to see one question per test on prime numbers. Be sure to understand what they are and how to find them. A prime number is a number that is only divisible by two numbers- itself and 1. For example, is a prime number because $1 * $ is its only factor. ( is not evenly divisible by 2, 3, 4, 5, 6, 7, 8, 9, or 10). 12 is NOT a prime number, because its factors are 1, 2, 3, 4, 6, and 12. It has more factors than just itself and 1. 1 is NOT a prime number, because its only factor is 1. The only even prime number is 2. Questions about primes come up fairly often on the SAT and understanding that 2 (and only 2!) is a prime number will be invaluable for solving many of these. A prime number $x$ is squared and then added to a different prime number, $y$. Which of the following could be the final result? An even number An odd number A positive number A. I onlyB. II onlyC. III onlyD. I and III onlyE. I, II, and III Now this question relies on your knowledge of both number relationships and primes. You know that any number squared (the number times itself) will be an even number if the original number was even, and an odd number if the original number was odd. Why? Because an even * an even = an even, and an odd * an odd = an odd ($6 * 6 = 36$ $7 * 7 = 49$). Next, we are adding that square to another prime number. You’ll also remember that an even number + an odd number is odd, an odd number + an odd number is even, and an even number + an even number is even. Knowing that 2 is a prime number, let’s replace x with 2. $2^2 = 4$. Now if y is a different prime number (as stipulated in the question), it must be odd, because the only even prime number is 2. So let’s say $y = 3$. $4 + 3 = 7$. So the end result is odd. This means II is correct. But what if both x and y were odd prime numbers? So let’s say that $x = 3$ and $y = 5$. So $3^2 = 9$. $9 + 5 = 14$. So the end result is even. This means I is correct. Now, for option number III, our results show that it is possible to get a positive number result, since both our results were positive. This means the final answer is E, I, II, and III If you forgot that 2 was a prime number, you would have picked D, I and III only, because there would have been no possible way to get an odd number. Remembering that 2 is a prime number is the key to solving this question. Another typical prime number question on the SAT will ask you to identify how many prime numbers fall in a certain range of numbers. How many prime numbers are between 30 and 50, inclusive? A. TwoB. ThreeC. FourD. FiveE. Six This might seem intimidating or time-consuming, but I promise you do NOT need to memorize a list of prime numbers. First, eliminate all even numbers from the list, as you know the only even prime number is 2. Next, eliminate all numbers that end in 5. Any number that ends is 5 or 0 is divisible by 5. Now your list looks like this: 31, 33, 37, 39, 41, 43, 47, 49 This is much easier to work with, but we need to narrow it down further. (You could start using your calculator here, or you can do this by hand.) A way to see if a number is divisible by 3 is to add the digits together. If that number is 3 or divisible by 3, then the final result is divisible by 3. For example, the number 31 is NOT divisible by 3 because $3 + 1 = 4$, which is not divisible by 3. However 33 is divisible by 3 because $3 + 3 = 6$, which is divisible by 3. So we can now eliminate 33 ($3 + 3 = 6$) and 39 ($3 + 9 = 12$) from the list. We are left with 31, 37, 41, 43, 47, 49. Now, to make sure you try every necessary potential factor, take the square root of the number you are trying to determine is prime. Any integer equal to or less than the square root will be a potential factor, but you do not have to try any numbers higher. Why? Well let’s take 36 as an example. Its factors are: 1, 2, 3, 4, 6, 9, 12, 18, and 36. But now look at the factor pairings. 1 36 2 18 3 12 4 9 6 6 (9 4) (12 3) (18 2) (36 1) After you get past 6, the numbers repeat. If you test out 4, you will know that 9 goes evenly into your larger number- no need to actually test 9 just to get 4 again! So all numbers less than or equal to a potential prime’s square root are the only potential factors you need to test. Going back to our list, we have 31, 37, 41, 43, 47, 49. Well the closest square root to 31 and 37 is 6. We already know that neither 2 nor 3 nor 5 factor evenly into 31 and 37. Neither do 4, or 6. You’re done. Both 31 and 37 must be prime. As for 41, 43, 47, and 49, the closest square root of these is 7. We already know that neither 2 nor 3 nor 5 factor evenly into 41, 43, 47, or 49. 7 is the exact square root of 49, so we know 49 is NOT a prime. As for 41, 43, and 47, neither 4 nor 6 nor 7 go into them evenly, so they are all prime. You are left with 31, 37, 41, 43, and 47. So your answer is D, there are five prime numbers (31, 37, 41, 43, and 47) between 30 and 50. Prime numbers, Prime Directive, either way I'm sure we'll live long and prosper. Absolute Values Absolute values are a concept that the SAT loves to use, as it is all too easy for students to make mistakes with absolute values. Expect to see one question on absolute values per test (though very rarely more than one). An absolute value is a representation of distance along a number line, forward or backwards. This means that an absolute value equation will always have two solutions. It also means that whatever is in the absolute value sign will be positive, as it represents distance along a number line and there is no such thing as a negative distance. An equation $|x + 3| = 14$, has two solutions: $x = $ $x = -17$ Why -17? Well $-17 + 3 = -14$ and, because it is an absolute value (and therefore a distance), the final answer becomes positive. So $|-14| = 14$ When you are presented with an absolute value, instead of doing the math in your head to find the negative and positive solution, rewrite the equation into two different equations. When presented with the above equation $|x + 3| = 14$, take away the absolute value sign and transform it into two equations- one with a positive solution and one with a negative solution. So $|x + 3| = 14$ becomes: $x + 3 = 14$ AND $x + 3 = -14$ Solve for $x$ $x = $ and $x = -17$ $|10 - k| = 3$ $|k - 5| = 8$. What is a value for $k$ that fulfills both equations above? We know that any given absolute value expression will have two solutions, so we must find the solution that each of these equations shares in common. For our first absolute value equation, we are trying to find the numbers for $k$ that, when subtracted from 10 will give us 3 and -3. That means our $k$ values will be 7 and 13. Why? Because $10 - 7 = 3$ and $10 - 13 = -3$ Now let's look at our second equation. We know that the two numbers for $k$ for $k - 5$ must give us both 8 and -8. This means our $k$ values will be 13 and -3. Why? Because $13 - 5 = 8$ and $-3 - 5 = -8$. 13 shows up as a solution for both problems, which means it is our answer. So our final answer is 13, this is the number for $k$ that can solve both equations. Consecutive Numbers Questions about consecutive numbers may or may not show up on your SAT. If they appear, it will be for a maximum of one question. Regardless, they are still an important concept for you to understand. Consecutive numbers are numbers that go continuously along the number line with a set distance between each number. So an example of positive, consecutive numbers would be: 4, 5, 6, 7, 8 An example of negative, consecutive numbers would be: -8, -7, -6, -5, -4 (Notice how the negative integers go from greatest to least- if you remember the basic guide to integers, this is because of how they lie on the number line in relation to 0) You can write unknown consecutive numbers out algebraically by assigning the first in the series a variable, $x$, and then continuing the sequence of adding 1 to each additional number. The sum of four positive, consecutive integers is 54. What is the first of these integers? If x is our first, unknown, integer in the sequence, so you can write all four numbers as: $x + (x + 1) + (x + 2) + (x + 3) = 54$ $4x + 6 = 54$ $4x = 48$ $x = 12$ So, because x is our first number in the sequence and $x= 12$, the first number in our sequence is 12. You may also be asked to find consecutive even or consecutive odd integers. This is the same as consecutive integers, only they are going up every other number instead of every number. This means there is a difference of two units between each number in the sequence instead of 1. An example of positive, consecutive even integers: 8, 10, 12, 14, 16 An example of positive, consecutive odd integers: 15, 17, 19, 21, 23 Both consecutive even or consecutive odd integers can be written out in sequence as: $x, x + 2, x + 4, x + 6$, etc. No matter if the beginning number is even or odd, the numbers in the sequence will always be two units apart. What is the median number in the sequence of five positive, consecutive odd integers whose sum is 185? $x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 185$ $5x + 20 = 185$ $5x = 165$ $x = 33$ So the first number in the sequence is 33. This means the full sequence is: 33, 35, 37, 39, 41 The median number in the sequence is 37. Bonus history lesson- Grover Cleveland is the only US president to have ever served two non-consecutive terms. Steps to Solving an SAT Integer Question Because SAT integer questions are so numerous and varied, there is no set way to approach them that is entirely separate from approaching other kinds of SAT math questions. But there are a few techniques that will help you approach your SAT integer questions (and by extension, most questions on SAT math). #1: Make sure the question requires an integer. If the question does NOT specify that you are looking for an integer, then any number- including decimals and fractions- are fair game. Always read the question carefully to make sure you are on the right track. #2: Use real numbers if you forget your integer rules. Forget whether positive, even consecutive integers should be written as $x + (x + 1)$ or $x + (x + 2)$? Test it out with real numbers! 14, 16, 18 are consecutive even integers. If $x = 14$, $16 = x + 2$, and $18 = x + 4$. This works for most all of your integer rules. Forget your exponent rules? Plug in real numbers! Forget whether an even * an even makes an even or an odd? Plug in real numbers! #3: Keep your work organized. Like with most SAT math questions, integer questions can seem more complex than they are, or will be presented to you in strange ways. Keep your work well organized and keep track of your values to make sure your answer is exactly what the question is asking for. Santa is magic and has to double-check his list. So make sure you double-check your work too! Test Your Knowledge 1. If $a^x * a^6 = a^24$ and $(a^3)^y = a^15$, what is the value of $x + y$? A. 9B. 12C. 23D. 30E. 36 2. If $48√48 = a√b$ where $a$ and $b$ are positive integers and $a b$, which of the following could be a value of $ab$? A. 48B. 96C. 192D. 576E. 768 3. What is the product of the smallest prime number that is greater than 50 and the greatest prime number that is less than 50? 4.If $j, k$, and $n$ are consecutive integers such that $0jkn$ and the units (ones) digit of the product $jn$ is 9, what is the units digit of $k$? A. 0B. 1C. 2D. 3E. 4 Answers: C, D, 2491, A Answer Explanations: 1. In this question, we are being asked both to multiply bases with exponents as well as take a base with an exponent to another exponent. Essentially, the question is testing us on whether or not we know our exponent rules. If we remember our exponent rules, then we know that we must add exponents when we are multiplying two of the same base together. So $a^x * a^6 = a^24$ = $a^{x + 6} = a^24$ $x + 6 = 24$ $x = 18$ We have our value for $x$. Now we must find our $y$. We also know that, when taking a base and exponent to another exponent, we must multiply the exponents. So $(a^3)^y = a^15$ = $a^{3 * y} = a^15$ $3 * y = 15$ $y = 5$ In the final step, we must add our $x$ and $y$ values together: $18 + 5 = 23$ So our final answer is C, 23. 2. We are starting with $48√48$ and we know we must reduce it. Why? Because we are told that our first $48 = a$ and our second $48 = b$ AND that $a b$. Right now our $a$ and $b$ are equal, but, by reducing the expression, we will be able to find an $a$ value that is greater than our $b$ So let's find all the factors of 48 to see if there are any perfect squares. 48 $1 * 48$ $2 * 24$ $3 * 16$ $4 * 12$ $6 * 8$ Two of these pairings have perfect squares. 16 is our largest perfect square, which means that it will be the number we must use to reduce $48√48$ down to its most reduced form. Though we are not explicitly asked to find the most reduced form of $48√48$, we can start there for now. So $48√48 = 48 * √16 * √3$ $48 * 4 *√3$ $192√3$ This means that our $a = 192$ and our $b = 3$, then: $ab = 192 * 3 = 576$ So our final answer is D, 576. (Special note: you'll notice how we are told to find one possible value for $ab$, not necessarily $ab$ when $48√48$ is at its most reduced. So if our above answer hadn't matched one of our answer options, we would have had to reduce $48√48$ only part way. $48√48 = 48 * √4 * √12$ $48 * 2 * √12$ $96√12$ This would make our $a = 96$ and our $b = 12$, meaning that our final answer for $ab$ would be $96 * 12 = 52$.) 3. This question requires us to be able to figure out which numbers are prime. Let us use the same methods we used during the above section on prime numbers. All prime numbers other than 2 will be odd and there is no prime number that ends in 5. So let's list the odd numbers (excluding ones that end in 5's) above and below 50. 41, 43, 47, 49, 51, 53, 57, 59 We are trying to find the ones closest to 50 on either side, so let's first test the highest number in the 40's. 49 is the perfect square of 7, which means it is divisible by more than just itself and 1. We can cross 49 off the list. 47 is not divisible by 3 because $7 + 4 = $ and is not divisible by 3. It is also not divisible by any even number (because an even * an even = an even), by 5, or by 7. This means it must be prime. (Why did we stop here? Remember that we only have to test potential factors up until the closest square root of the potential prime. $√47$ is between $6^2 = 36$ and $7^2 = 49$, so we tested 7 just to be safe. Once we saw that 7 could not go into 47, we proved that 47 is a prime.) 47 is our largest prime less than 50. Now let's test the smallest number greater than 50. 51 is odd, but $5 + 1 = 6$, which is divisible by 3. That means that 51 is also divisible by 3 and thus cannot be prime. 53 is not divisible by 3 because $5 + 3 = 8$, which is not divisible by 3. It is also not divisible by 5 or 7. Therefore it is prime. (Again, we stopped here because the closest square root to 53 is between 7 and 8. And 8 cannot be a prime factor because all of its multiples are even). This means our smallest prime less than 50 is 47 and our largest is 53. Now we just need to find the product of those two numbers. $47 * 53 = 2491$ Our final answer is 2491. 4. We are told that $j$, $k$, and $n$ are consecutive integers. We also know they are positive (because they are greater than 0) and that they go in ascending order, $j$ to $k$ to $n$. We are also told that $jn$ equals a number with a units digit of 9. So let's find all the ways to get a product of 9 with two numbers. $1 * 9$ $3 * 3$ The only way to get any number that ends in 9 (units digit 9) from the product of two numbers is in one of two ways: #1: Both the original numbers have a units digit of 3 #2: The two original numbers have units digits of 1 and 9, respectively. Now let's visualize positive consecutive integers. Positive consecutive integers must go up in order with a difference of 1 between each variable. So $j, k, n$ could look like any collection of three numbers along a consistent number line. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, , 12, 13, 14, 15, 16, etc. There is no possible way that the units digits of the first and last of three consecutive numbers could both be 3. Why? Because if one had a units digit of 3, the other would have to end in either 1 or 5. Take 13 as an example. If $j$ were 13, then $n$ would have to be 15. And if $n$ were 13, then $j$ would have to be . So we know that neither $j$ nor $n$ has a units digit of 3. Now let's see if there is a way that we can give $j$ and $n$ units digits of 1 and 9 (or 9 and 1). If $j$ were given a units digit of 1, $n$ would have a units digit of 3. Why? Picture $j$ as . $n$ would have to be 13, and $ * 13 = 143$, which means the units digit of their product is not 9. But what if $n$ was a number with a units digit of 1? $j$ would have a units digit of 9. Why? Picture $n$ as now. $j$ would be 9. $9 * = 99$. The units digit is 9. And if the last digit of $j$ is 9 and the numbers $j, k, \and n$ are consecutive, then $k$ has to end in 0. So our final answer is A, 0. The Take-Aways Integers and integer questions can be tricky for some students, as they often involve concepts not tested in high school level math classes (when’s the last time you dealt with integer remainders, for example?). But most integer questions are much simpler than they appear. If you know your definitions- integers, consecutive integers, absolute values, etc.- and you know how to pay attention to what the question is asking you to find, you’ll be able to solve most any integer question that comes your way. What’s Next? Whew! You’ve done your paces on integers, both basic and advanced. Now that you’ve tackled these foundational topics of the SAT math, make sure you’ve got a solid grasp of all the math topics covered by the SAT math section, so that you can take on the SAT with confidence. Find yourself running out of time on SAT math? Check out our article on how to buy yourself time and complete your SAT math problems before time’s up. Feeling overwhelmed? Start by figuring out your ideal score and check out how to improve a low SAT math score. Already have pretty good scores and looking to get a perfect 800 on SAT Math? Check out our article on how to get a perfect score written by a full SAT scorer. Want to improve your SAT score by 160 points? Check out our best-in-class online SAT prep program. We guarantee your money back if you don't improve your SAT score by 160 points or more. Our program is entirely online, and it customizes what you study to your strengths and weaknesses. If you liked this Math strategy guide, you'll love our program. Along with more detailed lessons, you'll get thousands of practice problems organized by individual skills so you learn most effectively. We'll also give you a step-by-step program to follow so you'll never be confused about what to study next. Check out our 5-day free trial:

TSS -- Therapeutic Support Staff or One to One Aide

TSS Therapeutic Support Staff or One to One Aide Definition: A TSS or Therapeutic Support Staff, is staff that supports individual students. They are often called one to one aides or wrap around staff. Therapeutic support staff are hired to work with an individual student. Their employment is usually named as an accommodation in that students IEP. TSS are often paid for or paid by the local (county) mental health agency rather than the school district. Qualifications:   Being a TSS does not require a college degree, but often graduates with degrees in psychology find work as a TSS while they are pursuing advanced degrees. Requirements for employment as a TSS or One on One (as they are often popularly referred to) may vary from state to state or agency to agency, but often some college is required.    Usually these positions are considered educational rather than custodial, and many states are trying to avoid using TSSs.   Some are economic, but some are educational, as a student with a TSS often becomes prompt dependent and unable to function independently. Responsibility:   A TSSs primary responsibility is to the student for whom they are hired. They may help the teacher or other students in order to create a positive environment for their student, but they are not supervised directly by the teacher, but by the IEP. Hopefully, a TSS will see him or herself as a part of the educational team.   There is no question that the teacher, as the leader in a classroom, should command the cooperation of the TSS.   Often a TSS is assigned so that a child can spent more time in a general education classroom, and will work one on one with the student to help him or her do age appropriate general education curricular tasks.   Sometimes the TSS will bring the students folder of modified word from the special education resource room to complete parallel.    It is important for the General Educator to communicate with the TSS to establish which general education tasks (especially in content, such as science or social studies) the student can do with the class, rather than what may be in their folder.   A Partnership:   Although the TSSs responsibility is for the student, when the special education teacher works closely with the TSS and the General Educator, it is more likely both the student and the classroom teacher will benefit.   When the other students in the general education classroom see Mr. Bob, or Ms. Lisa as partners in leadership, you can ask them to push   in with their student into learning centers or in small group discussion.   Modeling how to get the student more involved by fading support is also critical.   Also Known As: One to One Aide, Wrap Around, Wrap Around Aide Examples: Because of his self injurious behavior, Rodney has a TSS at school, who sees that Rodney does not bang his head on the tray of his chair, or on the wall.

Google in china Case Study Example | Topics and Well Written Essays - 750 words

Google in china - Case Study Example In return, the users have viewed its advertisement messages and images. As Google aims at making information useful and acceptable via its search engine, the online community has been useful to the company in promoting its performance and competitiveness within the global market. The company’s mission has also allowed it to participate in circumventing censorship of information by governments. The success of implementing the marketing strategy within Google is determined by its effectiveness in promoting access to information by societies, especially in countries, such as China, where the government is determined to suppress access (Jones, 2011). It is however notable that Google’s China operations are not aligned to its mission. In its endeavor to make information useful and acceptable within China, the company has been limited by the censorship of the government. Regardless of the dilemma surrounding the company’s values, principles and mission, the company entered the Chinese market. The company’s entry into China was motivated by the irresistible and large Chinese market, which would promote its advertising revenue. After Google’s online services in China were restored, the company officials claimed that it had not changed anything in its service offering (Jones, 2011). Users were hopeful that the company was able to maintain its mission for enhanced access to useful and acceptable information via its search engine. Nevertheless, the company’s users in China realized that they could not access some information. This revealed that the company’s searches were being censored even more by the government. For instance, sites on political information would not be accessed. These illustrations reveal that Google’s Chinese operations were not congruent with its mission. This is due to the fact that the information that was acceptable and useful to the Chinese people was still

Disadvantages of Performance-related Pay outweigh its Advantages Essay

Disadvantages of Performance-related Pay outweigh its Advantages - Essay Example Critics have analyzed performance-related pay differently, as many of the writers in various articles indicate that performance-related pay is a fruitful payment method due to which, there is more competition for positive working and people are more motivated towards effective task performance. On the other hand, there are also writers that have written articles negating the effectiveness of performance-related pay. According to the writers that are against the adoption of method of payment on the basis of basis, the payments are given to only those employees that are able to be close to the administration or management and that the pay is not given to them because of their effective working but on the basis of favouritism. Performance-related pay can have a positive as well as negative impact in various workplace environments. This paper discusses that performance related pay has many advantages but the disadvantages associated to it are overwhelming and devalue this mode of payment. The various forms of performance related pay are described after which, some authorial opinions are analyzed in terms of performance related pay and its effects. The advantages and disadvantages of performance related pay are analyzed and it is discussed that disadvantages outweigh advantages of performance related pay. In the end, the topic is concluded.

ACC 5 Essay Example | Topics and Well Written Essays - 1000 words

ACC 5 - Essay Example Management accounting is as important as production in the modern agricultural environment. The solution offered here is a responsibility center approach that sets up cost and profit centers. The system enables comparisons based on crops and land. It also lets the farm track performance on a year to year basis. The solution is long term and will ensure that the farm will run well even after the management is taken over by the next generation. The cost centers are for support, and stages of production. We have production cost centers for land owners. One cost center is for management. The cost centers are grouped under the profit centers associated with each commodity. The accounting techniques presented here will be applicable to any farm. The farms can have any combination of land ownership, equipment and crop. The responsibility for accounting is with the top management. The automated system lets the owner perform detailed analysis that would not be possible without a software solu tion. The solution uses responsibility accounting. This approach is aligned with the organizational structure. It also lets us control finances better. There is an individual cost center for each activity. Costs can be allocated according to the land ownership. We also have cost centers based on crop. Each crop has its own marketing cost center. All the cost centers are grouped by crop and function as profit centers. This solution is beneficial because management control can be exercised from the farm field to the profits. Costs are allocated fairly amongst the crops so that we know accurately how much money has been spent to produce a particular crop. The allocation base is selected based on the right measure of the costs. The costs can be subdivided between the cost centers according to the allocation base. The individual costs associated with the use of equipment are considered. The software used generates the financial statements required. These include cost allocations,

IRR v. MIRR Valuation Methods Research Paper Example | Topics and Well Written Essays - 2250 words

IRR v. MIRR Valuation Methods - Research Paper Example However, the MIRR valuation method still exhibits a number of limitations noticeable with the use of IRR technique, for instance, its inability to value investments that are mutually exclusive. Additionally, the teaching of both IRR and MIRR in learning institutions has been a cause of concern, with claims that the IRR technique has had more attention at the expense of the MIRR valuation method. This paper focuses on analyzing IRR and MIRR with regard to major issues of concern, emerging issues, factors that have been instrumental in the understanding of IRR and MIRR in class situations, and present and future applications of the two valuation methods. Keywords: IRR (Internal Rate of Return), MIRR (Modified Internal Rate of Return), NPV (Net Present Value) Table of Contents Abstract 2 Table of Contents 3 introduction 3 Main issues in IRR 4 Main issues in MIRR 6 New Learning in IRR 6 New Learning in MIRR 7 Class activities that have facilitated learning and understanding of IRR and MI RR 8 Specific current and future applications and 8 relevance in the workplace 8 Conclusion 10 References 11 introduction The pertinent question in the discussion about IRR and MIRR valuation methods lies in the differences that exist between the two investment appraisal methods. The chief difference in IRR and MIRR valuation methods is traceable to the factors that come into play when calculating the value of an investment with either of the methods. More specifically, the IRR valuation methods, which is more traditional form of the two, measures the worth of an investment with emphasis on internal factors, conspicuously overlooking the impact of interest rates and inflationary impact on the value of an investment. On the contrary, MIRR is a valuation technique that seeks to mitigate the impact of limitations brought about by IRR (Eagle, et al., 2008, p. 70). Just as the name implies, MIRR valuation method is a modification of the IRR valuation method. MIRR allows the value of the investment under query to show the impact of both future and present value of currencies at different times in the life of a project. Largely, IRR technique is an optimistic view on the value of an investment, while the MIRR is a more realistic view on the present and future value of an investment and is deemed more accurate than IRR valuation method (Kierulff, 2008, p. 328). This paper explores the variations between the IRR and MIRR valuation method at length, while taking into account the main issues surrounding the valuation techniques and the future and present applications of the methods. Main issues in IRR The major issue surrounding the IRR valuation method is the method’s inconsideration of environmental factors that have an impact on the value of an investment. The IRR approach compares the net present value of cash inflows and outflows. The point at which the negative cash flows and positive cash flows become equal is the IRR value. Another way to look at the valua tion equation is the point at which the difference between cash inflows and cash outflows equate to zero. In establishing what project to undertake in a scenario where the different projects are under comparison, the project with the highest internal rate of return gets preference over the rest of the projects. Even under this consideration, the IRR value has to exceed the cost of capital rate for the project to be economically viable (Kelleher & MacCormack, 2004, p. 1). Despite its contribution to

Ethics Theories Essay Example | Topics and Well Written Essays - 500 words

Ethics Theories - Essay Example In this case, there is little question that a theft of the drug would be ethical under a teleological and utilitarian model. Depending on the ethical approach chosen, breaking into the store to steal the drug could be considered either right or wrong. As stated above, a teleological analysis would justify the action as being right due to its potential to avoid a great harm, a loss of life, at the expense of some lost profit, which surely cannot weigh as heavily. On the other hand, a more duty-based approach such as deontological would require that the morality of the act itself be considered without regard to its consequences. Deontological ethics maintains that actions themselves have intrinsic moral value, and can be inherently good or bad. Arguably, stealing is wrong even if it ends up having a positive effect, and therefore a deontological analysis would require a determination that the action is wrong. In short, the ends never justify the means under such an analysis. Notifying employees of layoffs via e-mail is the right way because of the manner in which the notification was handled in this particular case.